To determine the applied voltage in this circuit, we can use Ohm's Law. Ohm's Law states that the voltage [tex]\( V \)[/tex] across a resistor is the product of the current [tex]\( I \)[/tex] flowing through the resistor and the resistance [tex]\( R \)[/tex] of the resistor. Mathematically, this is expressed as:
[tex]\[ V = I \times R \][/tex]
Given the problem:
- The current [tex]\( I \)[/tex] is 9 Amperes (A).
- The resistance [tex]\( R \)[/tex] is 43 Ohms ([tex]\(\Omega\)[/tex]).
We substitute these values into the Ohm's Law formula:
[tex]\[ V = 9 \, \text{A} \times 43 \, \Omega \][/tex]
When we perform the multiplication:
[tex]\[ V = 387 \, \text{V} \][/tex]
Therefore, the applied voltage in the circuit must be:
[tex]\[ \boxed{387 \, \text{V}} \][/tex]
From the given multiple choices:
- A. [tex]\( 387 \, A \)[/tex] is incorrect because the unit is Amperes (A), which measures current, not voltage.
- B. [tex]\( 4.8 \, V \)[/tex] is incorrect.
- C. [tex]\( 4.8 \, A \)[/tex] is incorrect because the unit is Amperes (A), which measures current, not voltage.
- D. [tex]\( 387 \, V \)[/tex] is the correct answer.
