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If the weight of an object is greater than the buoyant force acting on it, it will sink.

What is the weight of a block of iron with the dimensions of [tex]\(3.00 \text{ cm} \times 3.00 \text{ cm} \times 3.00 \text{ cm}\)[/tex]? The iron has a mass of [tex]\(213 \text{ g}\)[/tex].

Hint: Convert mass to weight using [tex]\( \text{Weight} = mg \)[/tex], where mass is in kilograms and gravity, [tex]\( g = 9.80 \text{ m/s}^2 \)[/tex].

A. [tex]\(213 \text{ g}\)[/tex]
B. [tex]\(2.09 \text{ N}\)[/tex]
C. [tex]\(2,090 \text{ N}\)[/tex]
D. [tex]\(0.213 \text{ kg}\)[/tex]



Answer :

GinnyAnswer
To determine the weight of a block of iron given its mass, follow these steps:

1. Convert the mass from grams to kilograms:
- The mass of the block of iron is given as [tex]\( 213 \)[/tex] grams.
- Since there are [tex]\( 1,000 \)[/tex] grams in a kilogram, convert the mass by dividing by [tex]\( 1,000 \)[/tex]:
[tex]\[ \text{Mass in kilograms} = \frac{213 \, \text{grams}}{1,000} = 0.213 \, \text{kg} \][/tex]

2. Calculate the weight using the formula [tex]\( W = mg \)[/tex]:
- Here, [tex]\( W \)[/tex] is the weight, [tex]\( m \)[/tex] is the mass in kilograms, and [tex]\( g \)[/tex] is the acceleration due to gravity.
- The acceleration due to gravity is provided as [tex]\( 9.80 \, \text{m/s}^2 \)[/tex].
- Substitute the mass and gravity into the formula:
[tex]\[ W = 0.213 \, \text{kg} \times 9.80 \, \text{m/s}^2 \][/tex]

3. Perform the multiplication:
- Calculate the product of [tex]\( 0.213 \, \text{kg} \times 9.80 \, \text{m/s}^2 \)[/tex]:
[tex]\[ W = 0.213 \times 9.80 = 2.0874 \, \text{N} \][/tex]

Hence, the weight of the block of iron is [tex]\( 2.0874 \, \text{N} \)[/tex].

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