Describe the end behavior of the following function:

[tex]\( F(x) = -x^5 + x^2 - x \)[/tex]

A. The graph of the function starts high and ends low.
B. The graph of the function starts high and ends high.
C. The graph of the function starts low and ends high.
D. The graph of the function starts low and ends low.



Answer :

To describe the end behavior of the function [tex]\( F(x) = -x^5 + x^2 - x \)[/tex], we need to analyze the term with the highest power, which determines the function's end behavior as [tex]\( x \)[/tex] approaches positive and negative infinity.

1. Identify the Leading Term:
The leading term of the function [tex]\( F(x) = -x^5 + x^2 - x \)[/tex] is [tex]\( -x^5 \)[/tex] because it has the highest power of [tex]\( x \)[/tex].

2. Analyze the Leading Term's Behavior:
- When [tex]\( x \)[/tex] approaches positive infinity ([tex]\( x \to +\infty \)[/tex]):
The leading term [tex]\( -x^5 \)[/tex] will dominate the behavior of the function. Since the coefficient of [tex]\( x^5 \)[/tex] is negative, the term [tex]\( -x^5 \)[/tex] will approach negative infinity. Hence, [tex]\( F(x) \to -\infty \)[/tex] as [tex]\( x \to +\infty \)[/tex].

- When [tex]\( x \)[/tex] approaches negative infinity ([tex]\( x \to -\infty \)[/tex]):
Similarly, for large negative values of [tex]\( x \)[/tex], the negative sign and the odd power of [tex]\( x \)[/tex] means that [tex]\( -x^5 \)[/tex] will be a large positive number. Therefore, [tex]\( -x^5 \to +\infty \)[/tex]. Hence, [tex]\( F(x) \to +\infty \)[/tex] as [tex]\( x \to -\infty \)[/tex].

3. Determine the Graph's End Behavior:
Based on the above analysis, the graph of [tex]\( F(x) = -x^5 + x^2 - x \)[/tex]:
- Starts from positive infinity as [tex]\( x \)[/tex] approaches negative infinity (the left side of the graph).
- Ends at negative infinity as [tex]\( x \)[/tex] approaches positive infinity (the right side of the graph).

Thus, the correct end behavior of the graph is:
Option A: The graph of the function starts high and ends low.