To determine what is missing from the given neutralization reaction:
[tex]\[ \text{HBr} + \text{KOH} \rightarrow \text{H}_2\text{O} + \ \ \ \ \ \text{?} \][/tex]
we need to understand what happens during a neutralization reaction. A neutralization reaction typically involves an acid and a base reacting to form water and a salt.
1. Identify the acid and base:
- HBr (hydrobromic acid) is the acid.
- KOH (potassium hydroxide) is the base.
2. Determine the ions produced:
- HBr dissociates into [tex]\( \text{H}^+ \)[/tex] (hydrogen ion) and [tex]\( \text{Br}^- \)[/tex] (bromide ion).
- KOH dissociates into [tex]\( \text{K}^+ \)[/tex] (potassium ion) and [tex]\( \text{OH}^- \)[/tex] (hydroxide ion).
3. Form water:
- The [tex]\( \text{H}^+ \)[/tex] ion from HBr combines with the [tex]\( \text{OH}^- \)[/tex] ion from KOH to form water ([tex]\( \text{H}_2\text{O} \)[/tex]).
[tex]\[ \text{H}^+ + \text{OH}^- \rightarrow \text{H}_2\text{O} \][/tex]
4. Form the salt:
- The remaining ions, [tex]\( \text{K}^+ \)[/tex] from KOH and [tex]\( \text{Br}^- \)[/tex] from HBr, combine to form the salt potassium bromide ([tex]\( \text{KBr} \)[/tex]).
[tex]\[ \text{K}^+ + \text{Br}^- \rightarrow \text{KBr} \][/tex]
Putting these steps together, we see that the complete neutralization reaction is:
[tex]\[ \text{HBr} + \text{KOH} \rightarrow \text{H}_2\text{O} + \text{KBr} \][/tex]
Therefore, the missing product in the reaction is KBr.
The correct answer is:
A. [tex]\( \text{KBr} \)[/tex]
