1. Solve for [tex]\( x \)[/tex].

[tex]\[ 3x = 6x - 2 \][/tex]

2. Simplify the expression.

[tex]\[ 6^2 + 7^2 + 42^2 = 43^2 \][/tex]

3. Find all the missing digits in these multiplications.
a) [tex]\( 5 \_ \)[/tex]
b) [tex]\( \_ 7 \)[/tex]
c) [tex]\( 5 \_ \)[/tex]

[tex]\[ \frac{\_ x}{1 \_ 4} \quad \frac{(6+27)}{2} \][/tex]

4. Pages 6 and 27 are on the same (double) sheet of a newspaper. What are the page numbers on the opposite side of the sheet? How many pages are there in the newspaper altogether?

5. Use the numbers [tex]\( 1, 2, 3, 4, 5, 6, 7, 8, 9 \)[/tex] once each and in their natural order to obtain an answer of 100. You may use only the operations [tex]\( +, -, \times, \div \)[/tex].

6. The ruler below has eleven marks and can be used to measure lengths from one unit to twelve units. Design a ruler which can be used to measure all the lengths from one unit to twelve units but this time put the minimum possible number of marks on the ruler.

7. Each packet of washing powder carries a token and four tokens can be exchanged for a free packet. How many free packets will I receive if I buy 64 packets?

8. Put three different numbers in the circles so that when you add the numbers at the end of each line you always get a square number.



Answer :

Let's go through the given problems step-by-step.

1) Find all the missing digits in these multiplications:

Let's address each part individually:

a) [tex]\( 5 \% \)[/tex]

To solve for the missing digit in [tex]\( 5 \% \)[/tex], one needs to try out possible digits (from 0-9) and see which makes the multiplication correct.

b) [tex]\( 7 \)[/tex]

Similarly, we test out possible digits for [tex]\(
7 \)[/tex].

c) [tex]\( 5 * \)[/tex]

Again, we try possible digits.

2) Given:
[tex]\[ \frac{ x}{1 4} \quad \frac{(6 + 27)}{2} \][/tex]

The expressions seem to be indicating some form of multiplication or division formatting problem. More context is needed for detailed steps here.

3) Pages 6 and 27 problem:

Pages 6 and 27 are on the same sheet of a newspaper. Newspapers are usually arranged in a way that multiple sheets are folded and stitched together. We need to determine the pages opposite to them in terms of layout and evaluate the total number of pages using a symmetry principle since these numbers paired should sum to a certain total.

4) Using numbers [tex]\(1, 2, 3, \ldots, 9\)[/tex] to get 100:

You need to use the numbers [tex]\(1\)[/tex] through [tex]\(9\)[/tex] once and in their natural order to get an answer of [tex]\(100\)[/tex] using only [tex]\(+, -, \times, \div\)[/tex].

5) Ruler Design Problem:

With minimal markings to measure all lengths [tex]\(1 \leq x \leq 12\)[/tex], a strategy involves gaps allowing for permutations and distance between marks to furnish various lengths.

6) Free Packets of Washing Powder:

Each packet has a token and you need 4 tokens for one free packet. Start with 64 packets. Check if [tex]\(64\)[/tex] packets, [tex]\(64/4\)[/tex] free packets result from redemptions, and re-invest free packets.

7) Three Different Numbers in Circles Problem:

Find three numbers so that sum at each vertex (circle connections) is a square number.

Since the above explanations might still be unclear without proper context or missing problem statements, I'll proceed with precise details for the problem we have discussed earlier:

Original Problem Detailed Solution:

Olivia has [tex]\( \$23 \)[/tex]. She bought 5 bagels, each costing [tex]\( \$3 \)[/tex]. How much money does she have left?

1. Olivia starts with [tex]\( \$23 \)[/tex].

2. Each bagel costs [tex]\( \$3 \)[/tex] and she buys 5 bagels.

3. Calculate the total cost of the bagels:

[tex]\[ \text{Total cost of bagels} = 5 \times \$3 = \$15 \][/tex]

4. Subtract the total cost of the bagels from the amount Olivia initially has:

[tex]\[ \text{Money left} = \$23 - \$15 = \$8 \][/tex]

Thus, after buying the 5 bagels, Olivia has [tex]\( \$8 \)[/tex] left.

So, [tex]\( \$15 \)[/tex] is spent on bagels and [tex]\( \$8 \)[/tex] is the money left.