Answered

You have 3 green pens and 2 red pens in a bag. What is the probability of pulling a green pen out on the first pull?

Explain your answer. (1 pt)
Correct answer. (1 pt)



Answer :

To find the probability of pulling a green pen out on the first pull, we need to follow these steps:

1. Determine the total number of pens in the bag:
- There are 3 green pens.
- There are 2 red pens.
- Therefore, the total number of pens is [tex]\( 3 + 2 = 5 \)[/tex].

2. Determine the number of favorable outcomes:
- The favorable outcome is pulling a green pen.
- The number of green pens is 3.

3. Calculate the probability:
- Probability is defined as the ratio of the number of favorable outcomes to the total number of possible outcomes.
- Hence, the probability of pulling a green pen is given by the formula:
[tex]\[ \text{Probability of green pen} = \frac{\text{Number of green pens}}{\text{Total number of pens}} = \frac{3}{5} \][/tex]

4. Simplify the fraction if possible:
- [tex]\(\frac{3}{5}\)[/tex] is already in its simplest form.

5. Convert to decimal format (if required):
- [tex]\(\frac{3}{5} = 0.6\)[/tex]

So, the probability of pulling a green pen out on the first pull is [tex]\( \frac{3}{5} \)[/tex] or 0.6.

Final Answer:
The probability of pulling a green pen out on the first pull is [tex]\( \frac{3}{5} \)[/tex] or 0.6.
Correct answer: 3/5

Explanation: There are a total of 5 pens in the bag (3 green + 2 red). The probability of pulling a green pen out on the first pull is the number of green pens divided by the total number of pens. Therefore, the probability is 3/5 or 60%.

(1 pt) for the correct answer and (1 pt) for the explanation.