Answer :
Sure! Let's find the ratio of moles for Carbon (C), Hydrogen (H), and Oxygen (O) given the number of moles in the sample: [tex]\(4.9875\)[/tex] moles of Carbon, [tex]\(7.9802\)[/tex] moles of Hydrogen, and [tex]\(2.00\)[/tex] moles of Oxygen.
First, we identify the smallest number of moles among the three. Comparing [tex]\(4.9875\)[/tex], [tex]\(7.9802\)[/tex], and [tex]\(2.00\)[/tex], we find that the smallest number is [tex]\(2.00\)[/tex] moles.
Next, we divide the number of moles of each element by this smallest number:
1. For Carbon (C):
[tex]\[ \frac{4.9875}{2.00} = 2.49375 \][/tex]
2. For Hydrogen (H):
[tex]\[ \frac{7.9802}{2.00} = 3.9901 \][/tex]
3. For Oxygen (O):
[tex]\[ \frac{2.00}{2.00} = 1.0 \][/tex]
So, the ratio of moles of Carbon (C), Hydrogen (H), and Oxygen (O) in the sample is:
[tex]\[ 2.49375 \ C : 3.9901 \ H : 1.0 \ O \][/tex]
Thus, [tex]\(C\)[/tex] has a ratio of [tex]\(2.49375\)[/tex] when divided by the smallest number of moles.
First, we identify the smallest number of moles among the three. Comparing [tex]\(4.9875\)[/tex], [tex]\(7.9802\)[/tex], and [tex]\(2.00\)[/tex], we find that the smallest number is [tex]\(2.00\)[/tex] moles.
Next, we divide the number of moles of each element by this smallest number:
1. For Carbon (C):
[tex]\[ \frac{4.9875}{2.00} = 2.49375 \][/tex]
2. For Hydrogen (H):
[tex]\[ \frac{7.9802}{2.00} = 3.9901 \][/tex]
3. For Oxygen (O):
[tex]\[ \frac{2.00}{2.00} = 1.0 \][/tex]
So, the ratio of moles of Carbon (C), Hydrogen (H), and Oxygen (O) in the sample is:
[tex]\[ 2.49375 \ C : 3.9901 \ H : 1.0 \ O \][/tex]
Thus, [tex]\(C\)[/tex] has a ratio of [tex]\(2.49375\)[/tex] when divided by the smallest number of moles.
