6. Simplify:

a. [tex]\((5+\sqrt{3})(3+\sqrt{2})\)[/tex]

b. [tex]\((\sqrt{5}+\sqrt{3})\)[/tex]

c. [tex]\((\sqrt{5}+\sqrt{3})^2\)[/tex]

d. [tex]\((\sqrt{5}-\sqrt{3})\)[/tex]



Answer :

Sure! Let's go through each part step-by-step:

### Part (a)
Simplify [tex]\((5 + \sqrt{3})(3 + \sqrt{2})\)[/tex].

To simplify this, we use the distributive property (also known as the FOIL method for binomials):

[tex]\[ (5 + \sqrt{3})(3 + \sqrt{2}) = 5 \cdot 3 + 5 \cdot \sqrt{2} + \sqrt{3} \cdot 3 + \sqrt{3} \cdot \sqrt{2} \][/tex]

Simplifying each term individually:

[tex]\[ = 15 + 5\sqrt{2} + 3\sqrt{3} + \sqrt{6} \][/tex]

So, the expression simplifies to:

[tex]\[ 15 + 5\sqrt{2} + 3\sqrt{3} + \sqrt{6} \approx 29.7167 \][/tex]

### Part (b)
Simplify [tex]\(\sqrt{5} + \sqrt{3}\)[/tex].

This expression is already in its simplest form. It approximately equals:

[tex]\[ \sqrt{5} + \sqrt{3} \approx 3.9681 \][/tex]

### Part (c)
Simplify [tex]\((\sqrt{5} + \sqrt{3})^2\)[/tex].

Using the binomial expansion formula [tex]\((a + b)^2 = a^2 + 2ab + b^2\)[/tex]:

[tex]\[ (\sqrt{5} + \sqrt{3})^2 = (\sqrt{5})^2 + 2(\sqrt{5})(\sqrt{3}) + (\sqrt{3})^2 \][/tex]

Simplifying each term individually:

[tex]\[ = 5 + 2\sqrt{15} + 3 = 8 + 2\sqrt{15} \][/tex]

So, the expression simplifies to:

[tex]\[ 8 + 2\sqrt{15} \approx 15.7460 \][/tex]

### Part (d)
Simplify [tex]\(\sqrt{5} - \sqrt{3}\)[/tex].

This expression is also already in its simplest form. It approximately equals:

[tex]\[ \sqrt{5} - \sqrt{3} \approx 0.5040 \][/tex]

Thus, summarizing the results:

- [tex]\((5 + \sqrt{3})(3 + \sqrt{2}) \approx 29.7167\)[/tex]
- [tex]\(\sqrt{5} + \sqrt{3} \approx 3.9681\)[/tex]
- [tex]\((\sqrt{5} + \sqrt{3})^2 \approx 15.7460\)[/tex]
- [tex]\(\sqrt{5} - \sqrt{3} \approx 0.5040\)[/tex]

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