Suppose that an object moves with velocity v(t)=12t−1/9t2 m/s from t=0 s to t=3 s. What is the total distance traveled



Answer :

Answer:

Step-by-step explanation:

at t=0

v(0)=12(0)-1/9(0)²=0

at~t=3

v(3)=12×3-1/9×3²=36-1=35

[tex]a=\frac{v(3)-v(0)}{3} =\frac{35-0}{3} =\frac{35}{3} \\v^2-u^2=2as\\35^2-0^2=2 \times \frac{35}{3} s\\s=35^2 \times \frac{3}{70}\\s=\frac{35 \times 3}{2} =\frac{105}{2} =52.5[/tex]