Solve the following problem and select your answer from the choices given.

Under ideal conditions, the population of a certain species doubles every nine years. If the population starts with 100 individuals, which of the following expressions would give the population of the species [tex]\( t \)[/tex] years after the start, assuming that the population is living under ideal conditions?

A. [tex]\( 2 \times 100^{9t} \)[/tex]

B. [tex]\( 2 \times 100^{\frac{t}{9}} \)[/tex]

C. [tex]\( 100 \times 2^{9t} \)[/tex]

D. [tex]\( 100 \times 2^{\frac{t}{9}} \)[/tex]



Answer :

To solve this problem, we need to understand the population growth under ideal conditions. The population doubles every nine years. Let [tex]\( t \)[/tex] be the number of years after the start.

Initially, the population is 100 individuals.

In exponential growth scenarios where the population doubles at a regular interval, the population [tex]\( P(t) \)[/tex] at time [tex]\( t \)[/tex] can be calculated using the formula:
[tex]\[ P(t) = P_0 \times 2^{\frac{t}{d}} \][/tex]
where:
- [tex]\( P_0 \)[/tex] is the initial population,
- [tex]\( t \)[/tex] is the time in years,
- [tex]\( d \)[/tex] is the doubling period in years.

Here, [tex]\( P_0 \)[/tex] is 100, and [tex]\( d \)[/tex] is 9 years.
Substituting these values into the formula gives us:
[tex]\[ P(t) = 100 \times 2^{\frac{t}{9}} \][/tex]

So, the correct expression for the population after [tex]\( t \)[/tex] years is:
[tex]\[ 100 \times 2^{\frac{t}{9}} \][/tex]

Thus, the correct choice matches the expression we derived:
[tex]\[ \boxed{100 \times 2^{\frac{t}{9}}} \][/tex]

Therefore, the answer is the fourth option.