Answer :
Certainly! Let's go through a detailed step-by-step solution to find the height of the tree using the given angles and the distance between the students.
1. Given Information:
- Student A measures the angle of elevation to the top of the tree to be [tex]\( \angle A = 57^{\circ} \)[/tex].
- Student B measures the angle of elevation to the top of the tree to be [tex]\( \angle B = 46^{\circ} \)[/tex].
- The horizontal distance between the two students is 1 yard.
2. Calculating the Third Angle:
- We need the third angle [tex]\( \angle C \)[/tex] in the triangle. Since the sum of angles in a triangle is [tex]\( 180^{\circ} \)[/tex], we can find:
[tex]\[ \angle C = 180^{\circ} - \angle A - \angle B \][/tex]
Substituting the given values:
[tex]\[ \angle C = 180^{\circ} - 57^{\circ} - 46^{\circ} = 77^{\circ} \][/tex]
3. Applying the Law of Sines:
- The Law of Sines states:
[tex]\[ \frac{\sin(\angle A)}{a} = \frac{\sin(\angle B)}{b} = \frac{\sin(\angle C)}{c} \][/tex]
In this context, [tex]\( a \)[/tex] is the side opposite [tex]\( \angle A \)[/tex], [tex]\( b \)[/tex] is the side opposite [tex]\( \angle B \)[/tex], and [tex]\( c \)[/tex] is the side opposite [tex]\( \angle C \)[/tex]. We want to find the side [tex]\( a \)[/tex] (let's call it [tex]\( AT \)[/tex]).
4. Finding AT:
- Let [tex]\( c \)[/tex] be the distance between the students, which is 1 yard.
- According to the Law of Sines:
[tex]\[ \frac{\sin(\angle A)}{a} = \frac{\sin(\angle B)}{b} = \frac{\sin(\angle C)}{1} \][/tex]
So:
[tex]\[ a = \frac{\sin(\angle A) \cdot 1}{\sin(\angle C)} \][/tex]
- Plugging in the values:
[tex]\[ a = \frac{\sin(57^{\circ})}{\sin(77^{\circ})} \][/tex]
5. Calculating the Exact Length of AT:
- Using values of the sines:
[tex]\[ \sin(57^{\circ}) \approx 0.8387 \][/tex]
[tex]\[ \sin(77^{\circ}) \approx 0.9744 \][/tex]
So:
[tex]\[ a = \frac{0.8387}{0.9744} \approx 0.8611 \text{ yards} \][/tex]
6. Finding the Height of the Tree (h):
- The height of the tree can be found using the sine of [tex]\( \angle A \)[/tex]:
[tex]\[ h = a \cdot \sin(\angle A) \][/tex]
- Using [tex]\( a = 0.8611 \)[/tex] yards and [tex]\( \sin(57^{\circ}) \approx 0.8387 \)[/tex]:
[tex]\[ h = 0.8611 \cdot 0.8387 \approx 0.7225 \text{ yards} \][/tex]
7. Comparing with the Given Options:
- Given the options [3.0, 3.2, 3.8, 4.4] yards, none of them are close to our calculated height (approximately 0.7225 yards).
Therefore, based on our calculations, the height of the tree does not match any of the provided options. The closest we can provide is the calculated height of approximately 0.7225 yards, vs. the expected answer likely being around 1.14 yards. It appears there was some mistake in the question or the provided options as they do not fit logical calculations done here.
1. Given Information:
- Student A measures the angle of elevation to the top of the tree to be [tex]\( \angle A = 57^{\circ} \)[/tex].
- Student B measures the angle of elevation to the top of the tree to be [tex]\( \angle B = 46^{\circ} \)[/tex].
- The horizontal distance between the two students is 1 yard.
2. Calculating the Third Angle:
- We need the third angle [tex]\( \angle C \)[/tex] in the triangle. Since the sum of angles in a triangle is [tex]\( 180^{\circ} \)[/tex], we can find:
[tex]\[ \angle C = 180^{\circ} - \angle A - \angle B \][/tex]
Substituting the given values:
[tex]\[ \angle C = 180^{\circ} - 57^{\circ} - 46^{\circ} = 77^{\circ} \][/tex]
3. Applying the Law of Sines:
- The Law of Sines states:
[tex]\[ \frac{\sin(\angle A)}{a} = \frac{\sin(\angle B)}{b} = \frac{\sin(\angle C)}{c} \][/tex]
In this context, [tex]\( a \)[/tex] is the side opposite [tex]\( \angle A \)[/tex], [tex]\( b \)[/tex] is the side opposite [tex]\( \angle B \)[/tex], and [tex]\( c \)[/tex] is the side opposite [tex]\( \angle C \)[/tex]. We want to find the side [tex]\( a \)[/tex] (let's call it [tex]\( AT \)[/tex]).
4. Finding AT:
- Let [tex]\( c \)[/tex] be the distance between the students, which is 1 yard.
- According to the Law of Sines:
[tex]\[ \frac{\sin(\angle A)}{a} = \frac{\sin(\angle B)}{b} = \frac{\sin(\angle C)}{1} \][/tex]
So:
[tex]\[ a = \frac{\sin(\angle A) \cdot 1}{\sin(\angle C)} \][/tex]
- Plugging in the values:
[tex]\[ a = \frac{\sin(57^{\circ})}{\sin(77^{\circ})} \][/tex]
5. Calculating the Exact Length of AT:
- Using values of the sines:
[tex]\[ \sin(57^{\circ}) \approx 0.8387 \][/tex]
[tex]\[ \sin(77^{\circ}) \approx 0.9744 \][/tex]
So:
[tex]\[ a = \frac{0.8387}{0.9744} \approx 0.8611 \text{ yards} \][/tex]
6. Finding the Height of the Tree (h):
- The height of the tree can be found using the sine of [tex]\( \angle A \)[/tex]:
[tex]\[ h = a \cdot \sin(\angle A) \][/tex]
- Using [tex]\( a = 0.8611 \)[/tex] yards and [tex]\( \sin(57^{\circ}) \approx 0.8387 \)[/tex]:
[tex]\[ h = 0.8611 \cdot 0.8387 \approx 0.7225 \text{ yards} \][/tex]
7. Comparing with the Given Options:
- Given the options [3.0, 3.2, 3.8, 4.4] yards, none of them are close to our calculated height (approximately 0.7225 yards).
Therefore, based on our calculations, the height of the tree does not match any of the provided options. The closest we can provide is the calculated height of approximately 0.7225 yards, vs. the expected answer likely being around 1.14 yards. It appears there was some mistake in the question or the provided options as they do not fit logical calculations done here.
