Answer:
The mass concentration of copper(II) fluoride in the prepared solution is approximately 5.6 g/L.
This can be calculated by using the formula:
concentration = (mass)/volume
In this case, the mass of copper(II) fluoride is 0.0282 g and the volume of the solution is 50 mL, which is equivalent to 0.05 L.
Therefore, the mass concentration is:
(0.0282 g) / (0.05 L) = 5.6 g/L