What is the pre-image of vertex [tex]\( A' \)[/tex] if the rule that created the image is [tex]\( r_{y \text{-axis}}(x, y) \rightarrow (-x, y) \)[/tex]?

A. [tex]\( (-4, 2) \)[/tex]
B. [tex]\( (-2, -4) \)[/tex]
C. [tex]\( A(2, 4) \)[/tex]
D. [tex]\( (4, -2) \)[/tex]



Answer :

To find the pre-image of vertex [tex]\( A' \)[/tex] given the transformation rule [tex]\( r_{y \text{-axis}}(x, y) \rightarrow(-x, y) \)[/tex], follow these steps:

1. Understand the transformation rule: The rule [tex]\( r_{y \text{-axis}}(x, y) \rightarrow(-x, y) \)[/tex] means that when a point [tex]\( (x, y) \)[/tex] is reflected over the y-axis, the x-coordinate is negated, while the y-coordinate remains unchanged.

2. Identify the coordinates of the image point [tex]\( A' \)[/tex]: The coordinates of the image point are given as [tex]\( A'(-4, 2) \)[/tex].

3. Apply the inverse transformation: To find the pre-image, we need to reverse the transformation. Since the rule is to negate the x-coordinate and keep the y-coordinate the same, the inverse transformation will also negate the x-coordinate back:
- The x-coordinate of the pre-image will be the negation of [tex]\(-4\)[/tex], which is [tex]\(4\)[/tex].
- The y-coordinate of the pre-image remains the same, which is [tex]\(2\)[/tex].

4. Determine the pre-image coordinates: Therefore, the pre-image of [tex]\( A'(-4, 2) \)[/tex] is at the coordinates [tex]\( (4, 2) \)[/tex].

Hence, the pre-image of vertex [tex]\( A' \)[/tex] is [tex]\( \boxed{(4, 2)} \)[/tex].