Two-fifths of one less than a number is less than three-fifths of one more than that number.

What numbers are in the solution set of this problem?

A. [tex]\( x \ \textless \ -5 \)[/tex]
B. [tex]\( x \ \textgreater \ -5 \)[/tex]
C. [tex]\( x \ \textgreater \ -1 \)[/tex]
D. [tex]\( x \ \textless \ -1 \)[/tex]



Answer :

We need to solve the following inequality:

[tex]\[ \frac{2}{5}(x - 1) < \frac{3}{5}(x + 1) \][/tex]

We will follow the step-by-step process to solve this inequality.

1. Eliminate the fractions: Multiply both sides of the inequality by 5 to get rid of the denominators:

[tex]\[ 5 \cdot \frac{2}{5}(x - 1) < 5 \cdot \frac{3}{5}(x + 1) \][/tex]

This simplifies to:

[tex]\[ 2(x - 1) < 3(x + 1) \][/tex]

2. Distribute the constants: Use the distributive property to expand both sides:

[tex]\[ 2x - 2 < 3x + 3 \][/tex]

3. Isolate the variable terms: To isolate [tex]\( x \)[/tex] on one side, subtract [tex]\( 2x \)[/tex] from both sides:

[tex]\[ -2 < x + 3 \][/tex]

4. Isolate the constant terms: Subtract 3 from both sides to isolate [tex]\( x \)[/tex]:

[tex]\[ -2 - 3 < x \][/tex]

Which simplifies to:

[tex]\[ -5 < x \][/tex]

This means that [tex]\( x \)[/tex] must be greater than -5.

Therefore, the solution set for the inequality is:

[tex]\[ (-5, \infty) \][/tex]

In interval notation, this means [tex]\( x \)[/tex] can be any number greater than -5.

So the correct answer is:

[tex]\[ x > -5 \][/tex]