Answer:
Step-by-step explanation:
[tex]cos\theta=\frac{21}{29}[/tex]
Make a right triangle with these values in Q1. The adjacent side is 21 and the hypotenuse is 29. If we want both sin and tan, we need the opposite side:
[tex]29^2-21^2=b^2[/tex]
b = 20
[tex]\frac{1}{sin\theta-tan\theta}=\frac{1}{\frac{20}{29}-\frac{20}{21} }=\frac{1}{-\frac{160}{609} }=-\frac{609}{160}[/tex]
