Step-by-step explanation:
To find the \(x\)-intercept and \(y\)-intercept of the equation \(2x + 4y = -12\), we need to determine the points where the line crosses the \(x\)-axis and \(y\)-axis respectively.
### \(x\)-Intercept
The \(x\)-intercept is the point where the line crosses the \(x\)-axis. At this point, \(y = 0\). So we substitute \(y = 0\) into the equation and solve for \(x\):
\[
2x + 4(0) = -12
\]
\[
2x = -12
\]
\[
x = -6
\]
So the \(x\)-intercept is \((-6, 0)\).
### \(y\)-Intercept
The \(y\)-intercept is the point where the line crosses the \(y\)-axis. At this point, \(x = 0\). So we substitute \(x = 0\) into the equation and solve for \(y\):
\[
2(0) + 4y = -12
\]
\[
4y = -12
\]
\[
y = -3
\]
So the \(y\)-intercept is \((0, -3)\).
### Summary
- The \(x\)-intercept is \((-6, 0)\).
- The \(y\)-intercept is \((0, -3)\).
Answer:
x= –6 and y= –3
Step-by-step explanation:
When you are given a number like this remember that the x and y intercept is = 0.
To find the y intercept divide 4y and –12 to get –3
To find the x intercept divide 2x and –12 to get –6