Certainly! Let's determine the expected number of dogs with each genotype in the given population.
We have the following information:
- Population size = 110
- Frequency of genotype CC ([tex]\(f(CC)\)[/tex]) = 0.01
- Frequency of genotype Cc ([tex]\(f(Cc)\)[/tex]) = 0.18
- Frequency of genotype cc ([tex]\(f(cc)\)[/tex]) = 0.81
To find the number of dogs with each genotype, we multiply the population size by the respective frequency for each genotype.
1. Number of dogs with genotype CC:
[tex]\[
\text{Number of dogs with genotype } CC = \text{Population size} \times f(CC)
\][/tex]
[tex]\[
= 110 \times 0.01 = 1.1
\][/tex]
2. Number of dogs with genotype Cc:
[tex]\[
\text{Number of dogs with genotype } Cc = \text{Population size} \times f(Cc)
\][/tex]
[tex]\[
= 110 \times 0.18 = 19.8
\][/tex]
3. Number of dogs with genotype cc:
[tex]\[
\text{Number of dogs with genotype } cc = \text{Population size} \times f(cc)
\][/tex]
[tex]\[
= 110 \times 0.81 = 89.1
\][/tex]
So, the expected number of dogs with each genotype in the population of 110 is:
- Dogs with genotype CC = 1.1
- Dogs with genotype Cc = 19.8
- Dogs with genotype cc = 89.1
