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Rewrite the chemical equations with correct formatting and spelling.

1. [tex]\( 6 \, \text{Fe} + \text{O}_2 \rightarrow 2 \, \text{FeO} \)[/tex]
Reactants: Fe, O[tex]\(_2\)[/tex]
Products: FeO

2. [tex]\( 2 \, \text{CO} + \text{O}_2 \rightarrow 2 \, \text{CO}_2 \)[/tex]
Reactants: CO, O[tex]\(_2\)[/tex]
Products: CO[tex]\(_2\)[/tex]

3. [tex]\( 4 \, \text{Al} + 3 \, \text{O}_2 \rightarrow 2 \, \text{Al}_2\text{O}_3 \)[/tex]
Reactants: Al, O[tex]\(_2\)[/tex]
Products: Al[tex]\(_2\)[/tex]O[tex]\(_3\)[/tex]

4. [tex]\( 2 \, \text{CO}_2 + 3 \, \text{O}_2 \rightarrow 2 \, \text{CO}_2\text{O}_3 \)[/tex]
Reactants: CO[tex]\(_2\)[/tex], O[tex]\(_2\)[/tex]
Products: CO[tex]\(_2\)[/tex]O[tex]\(_3\)[/tex]

5. [tex]\( 2 \, \text{Ca} + \text{O}_2 \rightarrow 2 \, \text{CaO} \)[/tex]
Reactants: Ca, O[tex]\(_2\)[/tex]
Products: CaO



Answer :

GinnyAnswer
The solution to this problem involves understanding the installation pattern of computers over a series of days. Let's break down the steps:

1. Initial Number of Computers:
- We start with an initial count of 9 computers.

2. Daily Installation Rate:
- Each day, an additional 5 computers are installed.

3. Number of Days:
- We are given a span of 4 days, from Monday to Thursday.

4. Computers Added Over 4 Days:
- To find this, we multiply the number of computers installed each day (5) by the number of days (4):
[tex]\[ \text{Computers added} = 5 \times 4 = 20 \][/tex]

5. Total Number of Computers:
- To find the total number of computers at the end of the 4 days, we add the initial number of computers (9) to the total number of added computers (20):
[tex]\[ \text{Total number of computers} = 9 + 20 = 29 \][/tex]

So, the detailed step-by-step solution concludes with the numbers:
- Computers added over 4 days: 20
- Total number of computers after 4 days: 29

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