Answer :
Step-by-step explanation:
Solution:
Here,
Let three positive whole numbers which are all different be a,b and c
Given that the median is 5 i.e. b=5
It's also given that
Mean=4
So,
(a+b+c)/3=4
or, a+b+c=12
Since, b=5
By putting the value of b. We get
a+5+c=12
or,a+c=7
We need two different positive whole numbers that add up to 7. Since a < 5 and c > 5
If a = 2 then c = 7 - 2 = 5
This configuration does not work because cmust be greater than b. Let's try other combinations:
a = 3 then c = 7 - 3 = 4
This configuration also does not work because a is less than b, and b is not different.
If a = 2 then c = 7 - 2 = 5
c must be different from b
Now, let's Identify a valid configuration:
If a = 3 then c = 7 - 3 = 3
This does not work as 4is less than 5..
If a = 1 then c = 6
This configuration satisfies all conditions:
-(a < b < c)
- (a = 1), (b = 5), (c = 6)
- (a + b + c = 1 + 5 + 6 = 12)
Therefore, the three different positive whole numbers are 1,5 and 6
