Write the following logarithmic expression as a single logarithm with coefficient 1:

[tex]\(\log 9 - 2 \log k\)[/tex]

A. [tex]\(\log \left(\frac{9}{k^2}\right)\)[/tex]

B. [tex]\(\log \left(9 k^2\right)\)[/tex]

C. [tex]\(\log \left(\frac{81}{k^2}\right)\)[/tex]

D. [tex]\(\log \left(\frac{9}{2 k}\right)\)[/tex]



Answer :

Sure, let's transform the given logarithmic expression [tex]\(\log 9 - 2 \log k\)[/tex] into a single logarithm with coefficient 1.

### Step-by-Step Solution

1. Identify the logarithms and their coefficients:
- The first part of the expression is [tex]\(\log 9\)[/tex].
- The second part is [tex]\(-2 \log k\)[/tex].

2. Use the properties of logarithms:
- Recall that [tex]\(a \log b = \log b^a\)[/tex].
- Therefore, [tex]\(-2 \log k\)[/tex] can be rewritten using this property:
[tex]\[ -2 \log k = \log k^{-2} \][/tex]

3. Combine the logarithms:
- Use the property that [tex]\(\log a - \log b = \log \left(\frac{a}{b}\right)\)[/tex]:
[tex]\[ \log 9 - \log k^2 = \log \left(\frac{9}{k^2}\right) \][/tex]

Thus, the expression [tex]\(\log 9 - 2 \log k\)[/tex] can be written as a single logarithm with coefficient 1:
[tex]\[ \log \left(\frac{9}{k^2}\right) \][/tex]

Therefore, the correct answer is:
[tex]\[ \log \left(\frac{9}{k^2}\right) \][/tex]