Martin is saving money to buy a new phone that costs [tex]$1,000 by selling trees. He is using an app to manage his sales, but it keeps a fraction of each sale. His net pay is modeled by the function \( P(x) = x^2 + 20x - 196 \), where \( x \) represents the number of sales.

How many sales does Martin need to make to earn $[/tex]1,000?



Answer :

To determine the number of sales Martin needs to make to earn [tex]$1,000 given the function \( P(x) = x^2 + 20x - 196 \), we need to solve the equation for \( x \) when \( P(x) = 1000 \). First, set up the equation: \[ x^2 + 20x - 196 = 1000 \] Then, move all terms to one side of the equation to set it to zero: \[ x^2 + 20x - 196 - 1000 = 0 \] Simplify: \[ x^2 + 20x - 1196 = 0 \] This is a quadratic equation in the standard form \( ax^2 + bx + c = 0 \) where \( a = 1 \), \( b = 20 \), and \( c = -1196 \). Now, solve this quadratic equation. One method to solve quadratic equations is to use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): 1. Calculate the discriminant: \[ \Delta = b^2 - 4ac \] \[ \Delta = 20^2 - 4 \cdot 1 \cdot (-1196) \] \[ \Delta = 400 + 4784 \] \[ \Delta = 5184 \] 2. Find the roots using the quadratic formula: \[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \] \[ x = \frac{-20 \pm \sqrt{5184}}{2 \cdot 1} \] \[ x = \frac{-20 \pm 72}{2} \] 3. Simplify each solution: \[ x_1 = \frac{-20 + 72}{2} \] \[ x_1 = \frac{52}{2} \] \[ x_1 = 26 \] \[ x_2 = \frac{-20 - 72}{2} \] \[ x_2 = \frac{-92}{2} \] \[ x_2 = -46 \] Since \( x \) represents the number of sales, it must be a real, non-negative number. Therefore, we discard the negative solution \( x = -46 \). Thus, Martin needs to make \(\boxed{26}\) sales to earn $[/tex]1,000.

The result is that Martin needs to make 26 sales to earn $1,000.

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