To determine how many liters would be occupied by 10.0 kg of wood with a density of 0.880 g/mL, follow these steps:
1. Convert the density to consistent units:
- Since we want the volume in liters and the mass is given in kilograms, we need to convert the density from g/mL to kg/L.
- Density Conversion: 1 g/mL is equivalent to 1,000 kg/L.
- Thus, 0.880 g/mL is equivalent to [tex]\( 0.880 \times 0.001 = 0.00088 \)[/tex] kg/L.
2. Use the formula for density:
- Density (ρ) is defined as mass (m) divided by volume (V). Hence, [tex]\( \rho = \frac{m}{V} \)[/tex].
- Rearrange the formula to solve for volume: [tex]\( V = \frac{m}{\rho} \)[/tex].
3. Plug in the given values:
- Mass (m) = 10.0 kg
- Density (ρ) = 0.00088 kg/L
4. Calculate the volume:
- Volume (V) = [tex]\( \frac{10.0 \text{ kg}}{0.00088 \text{ kg/L}} \)[/tex].
5. Perform the division:
- Volume (V) = 11,363.636363636364 liters.
Therefore, 10.0 kg of wood with a density of 0.880 g/mL would occupy approximately 11,363.64 liters.
