Use z scores to compare the given values. the tallest living man at one time had a height of 232 cm. the shortest living man at that time had a height of 145.2 cm. heights of men at that time had a mean of 176.81 cm and a standard deviation of 5.16 cm. which of these two men had the height that was more extreme



Answer :

Answer:

Step-by-step explanation:

To compare the heights of the tallest and shortest living men using z-scores, we need to calculate the z-score for each height and then determine which one is more extreme.

Given information:

Tallest man's height: 232 cm

Shortest man's height: 145.2 cm

Mean height: 176.81 cm

Standard deviation: 5.16 cm

Step 1: Calculate the z-score for the tallest man's height.

z-score = (Tallest man's height - Mean height) / Standard deviation

z-score = (232 cm - 176.81 cm) / 5.16 cm

z-score = 10.74

Step 2: Calculate the z-score for the shortest man's height.

z-score = (Shortest man's height - Mean height) / Standard deviation

z-score = (145.2 cm - 176.81 cm) / 5.16 cm

z-score = -6.10

Step 3: Determine which height is more extreme.

The absolute value of the z-score indicates how many standard deviations the value is from the mean. The larger the absolute value of the z-score, the more extreme the value.

In this case, the absolute value of the z-score for the tallest man's height (10.74) is larger than the absolute value of the z-score for the shortest man's height (6.10).

Therefore, the tallest man's height is more extreme compared to the shortest man's height.