Type the correct answer in the box. Round your answer to the nearest hundredth.

Element [tex]\(X\)[/tex] has two isotopes. The table gives information about these isotopes.

[tex]\[
\begin{array}{|c|c|c|}
\hline
\text{Isotope} & \text{Atomic Mass (amu)} & \text{Abundance (\%)} \\
\hline
\text{X-63} & 62.9296 & 69.15 \\
\hline
\text{X-65} & 64.9278 & 30.85 \\
\hline
\end{array}
\][/tex]

The average atomic mass of element [tex]\(X\)[/tex] is [tex]\(\boxed{\phantom{0}}\)[/tex] amu.



Answer :

To determine the average atomic mass of element [tex]\( X \)[/tex], we need to use the information provided about its isotopes' atomic masses and their respective abundances. We will follow the steps below:

1. Identify the atomic masses and their respective abundances from the table:
- Isotope [tex]\( X \)[/tex]-63 has an atomic mass of 62.9296 amu and an abundance of 69.15%.
- Isotope [tex]\( X \)[/tex]-65 has an atomic mass of 64.9278 amu and an abundance of 30.85%.

2. Convert the percentages of abundance into decimal form by dividing by 100:
- [tex]\( 69.15\% = \frac{69.15}{100} = 0.6915 \)[/tex]
- [tex]\( 30.85\% = \frac{30.85}{100} = 0.3085 \)[/tex]

3. Calculate the contribution of each isotope to the average atomic mass:
- Contribution of [tex]\( X \)[/tex]-63: [tex]\( 62.9296 \times 0.6915 \)[/tex]
- Contribution of [tex]\( X \)[/tex]-65: [tex]\( 64.9278 \times 0.3085 \)[/tex]

4. Add these contributions together to get the total average atomic mass:
[tex]\[ \text{Average atomic mass} = (62.9296 \times 0.6915) + (64.9278 \times 0.3085) \][/tex]

5. Perform the calculations for the contributions:
[tex]\[ 62.9296 \times 0.6915 \approx 43.5102 \][/tex]
[tex]\[ 64.9278 \times 0.3085 \approx 20.0398 \][/tex]

6. Sum these contributions to find the total average atomic mass:
[tex]\[ 43.5102 + 20.0398 = 63.55 \][/tex]

7. Finally, round the result to the nearest hundredth:
[tex]\[ 63.55 \, \text{amu} \][/tex]

Thus, the average atomic mass of element [tex]\( X \)[/tex] is 63.55 amu.