Express the sum in the simplest form.

[tex]\[
\frac{2y}{y+2} + \frac{4}{y+2}
\][/tex]

A. [tex]\(\frac{8y}{y+2}\)[/tex]

B. [tex]\(\frac{y-2}{y+2}\)[/tex]

C. [tex]\(\frac{y}{y+2}\)[/tex]

D. 2



Answer :

Sure, let's simplify the expression step-by-step.

Given:
[tex]\[ \frac{2 y}{y+2} + \frac{4}{y+2} \][/tex]

1. Notice that both terms in the sum have the same denominator, [tex]\( y + 2 \)[/tex]. When adding fractions with the same denominator, you simply add the numerators together:

[tex]\[ \frac{2 y + 4}{y+2} \][/tex]

2. Next, factor the numerator:

[tex]\[ 2 y + 4 = 2(y + 2) \][/tex]

So the expression now becomes:

[tex]\[ \frac{2(y + 2)}{y + 2} \][/tex]

3. Since the numerator and the denominator are the same (except for the factor 2 in the numerator), we can cancel out [tex]\( y + 2 \)[/tex]:

[tex]\[ \frac{2(y + 2)}{y + 2} = 2 \][/tex]

Thus, the expression simplifies to [tex]\( 2 \)[/tex].

So, the correct answer is:
[tex]\[ \boxed{2} \][/tex]