Solve the following equations:

a) [tex]\( 49^{2x} \times \left(\frac{1}{7}\right)^{y-4} = \frac{1}{343} \)[/tex]

b) [tex]\( 3^{x+3} \div \frac{1}{27} = \frac{1}{9} \)[/tex]



Answer :

Let's analyze and solve the system of equations step by step.

### First Equation

The first equation given is:
[tex]\[ 49^{2x} \times \left(\frac{1}{7}\right)^{y-4} = \frac{1}{343} \][/tex]

#### Step-by-Step Solution:

1. Rewrite in terms of the same base:
- Notice that [tex]\( 49 = 7^2 \)[/tex] and [tex]\( 343 = 7^3 \)[/tex].
- The equation [tex]\(49^{2x}\)[/tex] can be rewritten as [tex]\((7^2)^{2x} = 7^{4x}\)[/tex].
- The fraction [tex]\(\left(\frac{1}{7}\right)^{y-4}\)[/tex] can be written as [tex]\(7^{-(y-4)}\)[/tex].
- The right-hand side [tex]\(\frac{1}{343}\)[/tex] can be written as [tex]\(7^{-3}\)[/tex].

2. Substitute these values:
[tex]\[ 7^{4x} \times 7^{-(y-4)} = 7^{-3} \][/tex]

3. Combine the exponents:
Using the property [tex]\(a^m \times a^n = a^{m+n}\)[/tex], we get:
[tex]\[ 7^{4x - (y - 4)} = 7^{-3} \][/tex]
[tex]\[ 7^{4x - y + 4} = 7^{-3} \][/tex]

4. Set the exponents equal to each other:
Since the bases are the same, the exponents must be equal:
[tex]\[ 4x - y + 4 = -3 \][/tex]

5. Simplify the equation:
[tex]\[ 4x - y = -7 \][/tex]

This gives us the first equation in a simplified linear form:
[tex]\[ 4x - y = -7 \][/tex]

Let's call this Equation (1).

### Second Equation

The second equation given is:
[tex]\[ 3^{x+3} \div \frac{1}{279} = \frac{1}{9} \][/tex]

#### Step-by-Step Solution:

1. Rewrite in terms of the same base:
- The equation [tex]\(\frac{1}{279}\)[/tex] can be simplified as [tex]\(3^{-1}\)[/tex] because [tex]\(279 \neq 3^3\)[/tex], let's assume there was a slight mistake here and take the original base from fractional exponents [tex]\( \)[/tex].
- The right-hand side [tex]\(\frac{1}{9}\)[/tex] can be written as [tex]\(3^{-2}\)[/tex].

2. Simplify the equation:
[tex]\[ 3^{x+3} \times 3^{-1} = 3^{-2} \][/tex]

3. Combine the exponents:
Using the property [tex]\(a^m \times a^n = a^{m+n}\)[/tex], we get:
[tex]\[ 3^{(x+3) + (-1)} = 3^{-2} \][/tex]
[tex]\[ 3^{x + 2} = 3^{-2} \][/tex]

4. Set the exponents equal to each other:
Since the bases are the same, the exponents must be equal:
[tex]\[ x + 2 = -2 \][/tex]

5. Solve for [tex]\(x\)[/tex]:
[tex]\[ x = -2 - 2 \][/tex]
[tex]\[ x = -6 \][/tex]

We have the value of [tex]\(x\)[/tex]:
[tex]\[ x = -6 \][/tex]

### Substitute [tex]\(x = -6\)[/tex] into Equation (1)

Using Equation (1):
[tex]\[ 4x - y = -7 \][/tex]

1. Substitute [tex]\(x = -6\)[/tex]:
[tex]\[ 4(-6) - y = -7 \][/tex]
[tex]\[ -24 - y = -7 \][/tex]

2. Solve for [tex]\(y\)[/tex]:
[tex]\[ -y = -7 + 24 \][/tex]
[tex]\[ -y = 17 \][/tex]
[tex]\[ y = -17 \][/tex]

### Final Solution

[tex]\[ x = -6 \][/tex]
[tex]\[ y = -17 \][/tex]

The pair [tex]\((x, y)\)[/tex] that satisfies both equations is [tex]\((-6, -17)\)[/tex].