Answer :

iloveonedirection
[tex]4(log _{3} 1/27) =x[/tex]
[tex]log _{3} \frac{1}{27}^4 =x[/tex]

Now remember: [tex]b^y=x \\ equals \\ log _{b}x=y[/tex]

[tex]3^x = \frac{1}{27}^4[/tex]
[tex]3^x = \frac{1}{531441} [/tex]
[tex]log _{3} \frac{1}{531441} =x[/tex]
[tex] \frac{ln\frac{1}{531441}}{ln3} = x[/tex]
[tex]\frac{1}{531441} = 0.000002[/tex]
you can now enter this into your calculator...

Answer: x = -0.083
Heyy!

So, iloveonedirection's response would have been correct if there weren't parenthesis around the log equation, its a mistake that literally happens to everyone, I know from experience lol.

Ok so first, lets simplify (log3 1/27):
log(base) of answer= exponent, so we can determine that the base is 3, the answer is 1/27 and the exponent is what we want. so:
3^x = 1/27 , so x= -3 when you solve.
this allows you to substitute -3 for (log3 1/27)

now that leaves you with:
4 (-3) = x
-12 =x

to check your work, just use the calculator:
[log (1/27) /log 3] * 4
which = -12

Hope you understand what I'm trying to say. ;)
Tip: always plug in to a calculator if you aren't sure, have extra time on a test, or anything else lol
Good luck love! you got this :) xx

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