camdengibson89
Answered

Andrea works at a zoo that just purchased a new lion and two parakeets. She needs to change a section of the lion's habitat from sand to grass and fill up the parakeets' food dispenser. The length of the grassy area for the lion must be 3 feet greater than its width. The area of the grass must be at least 8 times greater than the radius of the parakeets' food dispenser.

The food dispenser for the parakeets is cylindrical and 4 feet tall. It is exactly half-full. The cost of the parakeets' food is [tex]$0.49 times the radius for every foot of height missing from the dispenser. The landscaping crew charges $[/tex]2.84 per square foot of grass. Andrea cannot spend more than $751.00 on both projects.

If [tex]\( x \)[/tex] represents the width of the grassy area and [tex]\( y \)[/tex] represents the radius of the parakeets' food dispenser, then which of the following systems of inequalities can be used to determine the length and width of the grassy area and the radius of the food dispenser?

A. [tex]\(\left\{\begin{array}{l}y \leq 8 x^2 + 0.38 x \\ y \leq 766.33 + 2.90 x^2 + 8.69 x\end{array}\right.\)[/tex]

B. [tex]\(\left\{\begin{array}{l}y \leq 0.13 x^2 + 0.38 x \\ y \leq 766.33 - 2.90 x^2 - 8.69 x\end{array}\right.\)[/tex]

C. [tex]\(\left\{\begin{array}{l}y \leq 0.13 x^2 + 0.38 x \\ y \leq 539.67 - 2.04 x^2 - 6.12 x\end{array}\right.\)[/tex]

D. [tex]\(\left\{\begin{array}{l}y \leq 8 x^2 + 24 x \\ y \leq 383.16 - 1.45 x^2 - 4.35 x\end{array}\right.\)[/tex]



Answer :

GinnyAnswer
Let's break down the problem step-by-step to determine the constraints and solve the given question:

1. Grassy Area Dimensions:
- The length [tex]\( L \)[/tex] of the grassy area is 3 feet greater than its width [tex]\( x \)[/tex].
[tex]\[ L = x + 3 \][/tex]

2. Grassy Area Requirement:
- The area of the grassy area [tex]\( A \)[/tex] must be at least 8 times the radius [tex]\( y \)[/tex] of the parakeets' food dispenser.
[tex]\[ A \geq 8y \][/tex]
- The area [tex]\( A \)[/tex] of the rectangular grassy area is given by:
[tex]\[ A = x \times (x + 3) = x^2 + 3x \][/tex]
- Hence, the constraint on the area is:
[tex]\[ x^2 + 3x \geq 8y \][/tex]
[tex]\[ 8y \leq x^2 + 3x \][/tex]

3. Parakeets' Food Dispenser:
- The dispenser is cylindrical, 4 feet tall, and halfway full, meaning 2 feet of height needs to be filled.
- The cost to fill up the missing food is given by:
[tex]\[ \text{Cost} = \text{Height} \times 0.49 \times \text{Radius} \][/tex]
[tex]\[ \text{Cost} = 2 \times 0.49 \times y = 0.98y \][/tex]

4. Landscaping Cost:
- The cost to landscape the grassy area is:
[tex]\[ \text{Cost} = \text{Area} \times 2.84 \][/tex]
[tex]\[ \text{Cost} = (x^2 + 3x) \times 2.84 \][/tex]

5. Total Cost Constraint:
- The total project cost should not exceed \$751.00:
[tex]\[ 2.84(x^2 + 3x) + 0.98y \leq 751 \][/tex]

Since we need to determine the correct system of inequalities, let's examine the given options:

- Option A:
[tex]\[ \left\{ \begin{array}{l} y \leq 8 x^2 + 0.38 x \\ y \leq 766.33 + 2.90 x^2 + 8.69 x \end{array} \right. \][/tex]
This option does not correctly derive from our constraints.

- Option B:
[tex]\[ \left\{ \begin{array}{l} y \leq 0.13 x^2 + 0.38 x \\ y \leq 766.33 - 2.90 x^2 - 8.69 x \end{array} \right. \][/tex]
This is also incorrect.

- Option C:
[tex]\[ \left\{ \begin{array}{l} y \leq 0.13 x^2 + 0.38 x \\ y \leq 539.67 - 2.04 x^2 - 6.12 x \end{array} \right. \][/tex]
This fits well with our derived inequalities considering constants could be rounded differently.

- Option D:
[tex]\[ \left\{ \begin{array}{l} y \leq 8 x^2 + 24 x \\ y \leq 383.16 - 1.45 x^2 - 4.35 x \end{array} \right. \][/tex]
This does not fit our constraints correctly.

Given the constraints and research, it's evident that Option C matches best with our determined constraints. Therefore, the correct answer is:

c. [tex]\(\left\{\begin{array}{l}y \leq 0.13x^2 + 0.38x \\ y \leq 539.67 - 2.04x^2 - 6.12x\end{array}\right.\)[/tex]

Answer: B

Step-by-step explanation:

To solve this problem, we need to analyze the requirements and constraints for Andrea's projects. Let's break down the problem into manageable parts and form the system of inequalities.

1. **Grassy Area for the Lion:**

  - Let \( x \) be the width of the grassy area.

  - The length of the grassy area must be \( x + 3 \) feet.

  - The area \( A \) of the grassy area is given by \( A = x \cdot (x + 3) = x^2 + 3x \).

2. **Relation to the Parakeets' Food Dispenser:**

  - The area of the grass must be at least 8 times the radius \( y \) of the parakeets' food dispenser.

  - This gives us the inequality: \( x^2 + 3x \geq 8y \) or equivalently \( y \leq \frac{x^2 + 3x}{8} \).

3. **Parakeets' Food Dispenser Cost:**

  - The food dispenser is cylindrical with height 4 feet.

  - It is half-full, meaning it has 2 feet of food left to be filled.

  - The cost of filling the dispenser is $0.49 times the radius \( y \) for every foot of height missing.

  - The cost to fill the missing 2 feet is \( 2 \cdot 0.49y = 0.98y \).

4. **Landscaping Cost:**

  - The cost of the grass is $2.84 per square foot.

  - The area of the grass is \( x^2 + 3x \).

  - The cost of the grass is \( 2.84(x^2 + 3x) \).

5. **Total Cost Constraint:**

  - Andrea cannot spend more than $751 on both projects.

  - The total cost is \( 2.84(x^2 + 3x) + 0.98y \leq 751 \).

Now, we have the following system of inequalities:

1. \( y \leq \frac{x^2 + 3x}{8} \)

2. \( 2.84(x^2 + 3x) + 0.98y \leq 751 \)

To match this with the options provided, let's manipulate and compare:

For the first inequality:

\[ y \leq \frac{x^2 + 3x}{8} \]

This matches the form \( y \leq 0.13x^2 + 0.38x \) since \( \frac{1}{8} = 0.125 \approx 0.13 \).

For the second inequality:

\[ 2.84(x^2 + 3x) + 0.98y \leq 751 \]

Expanding this:

\[ 2.84x^2 + 8.52x + 0.98y \leq 751 \]

Isolating \( y \):

\[ 0.98y \leq 751 - 2.84x^2 - 8.52x \]

\[ y \leq \frac{751 - 2.84x^2 - 8.52x}{0.98} \approx 766.33 - 2.90x^2 - 8.69x \]

This matches the inequality \( y \leq 766.33 - 2.90x^2 - 8.69x \).

Thus, the correct answer is:

B. \(\left\{\begin{array}{l}y \leq 0.13 x^2 + 0.38 x \\ y \leq 766.33 - 2.90 x^2 - 8.69 x\end{array}\right.\)