Consider the function represented by the equation [tex]\(6q = 3s - 9\)[/tex]. Write the equation in function notation, where [tex]\(q\)[/tex] is the independent variable.

A. [tex]\(f(a) = \frac{1}{2}a - \frac{3}{2}\)[/tex]
B. [tex]\(f(q) = 2s + 3\)[/tex]
C. [tex]\(f(s) = \frac{1}{2}s - \frac{3}{2}\)[/tex]
D. [tex]\(f(q) = 2q + 3\)[/tex]



Answer :

To start, we are given the equation [tex]\( 6q = 3s - 9 \)[/tex]. Our goal is to express [tex]\( s \)[/tex] in terms of [tex]\( q \)[/tex] and then put this expression into function notation.

1. Begin with the given equation:
[tex]\[ 6q = 3s - 9 \][/tex]

2. To isolate [tex]\( s \)[/tex], first add 9 to both sides of the equation:
[tex]\[ 6q + 9 = 3s \][/tex]

3. Now, divide both sides by 3 to solve for [tex]\( s \)[/tex]:
[tex]\[ \frac{6q + 9}{3} = s \][/tex]

Simplifying the right-hand side:
[tex]\[ s = \frac{6q}{3} + \frac{9}{3} \][/tex]
[tex]\[ s = 2q + 3 \][/tex]

4. Now, express [tex]\( s \)[/tex] as [tex]\( f(q) \)[/tex] in function notation:
[tex]\[ f(q) = 2q + 3 \][/tex]

From the options provided, the correct one that matches the function [tex]\( s = 2q + 3 \)[/tex] is:

[tex]\[ f(q) = 2q + 3 \][/tex]

Therefore, the correct choice is [tex]\( f(q) = 2q + 3 \)[/tex].