The midpoint of [tex]\( \bar{E} \)[/tex] is point [tex]\( P \)[/tex] at [tex]\((-6,-2)\)[/tex]. If point [tex]\( E \)[/tex] is at [tex]\((2,-4)\)[/tex], what are the coordinates of point [tex]\( F \)[/tex]?

A. [tex]\((-14,0)\)[/tex]
B. [tex]\((-10,-8)\)[/tex]
C. [tex]\((-5,3)\)[/tex]



Answer :

To solve for the coordinates of point [tex]\( F \)[/tex] given the midpoint [tex]\( P \)[/tex] of segment [tex]\( \bar{EF} \)[/tex] and the coordinates of point [tex]\( E \)[/tex], follow these steps:

1. Identify the given coordinates:
- Point [tex]\( P \)[/tex] is [tex]\((-6, -2)\)[/tex]
- Point [tex]\( E \)[/tex] is [tex]\((2, -4)\)[/tex]

2. Recall the midpoint formula:
[tex]\[ P = \left(\frac{x_E + x_F}{2}, \frac{y_E + y_F}{2}\right) \][/tex]
where [tex]\( (x_E, y_E) \)[/tex] are the coordinates of point [tex]\( E \)[/tex] and [tex]\( (x_F, y_F) \)[/tex] are the coordinates of point [tex]\( F \)[/tex].

3. Set up the equations for the midpoint coordinates:
- For the x-coordinate:
[tex]\[ -6 = \frac{2 + x_F}{2} \][/tex]
- For the y-coordinate:
[tex]\[ -2 = \frac{-4 + y_F}{2} \][/tex]

4. Solve for [tex]\( x_F \)[/tex] and [tex]\( y_F \)[/tex]:
- First, solve the x-coordinate equation:
[tex]\[ -6 = \frac{2 + x_F}{2} \][/tex]
Multiply both sides by 2 to eliminate the denominator:
[tex]\[ -12 = 2 + x_F \][/tex]
Subtract 2 from both sides:
[tex]\[ x_F = -14 \][/tex]

- Next, solve the y-coordinate equation:
[tex]\[ -2 = \frac{-4 + y_F}{2} \][/tex]
Multiply both sides by 2 to eliminate the denominator:
[tex]\[ -4 = -4 + y_F \][/tex]
Add 4 to both sides:
[tex]\[ y_F = 0 \][/tex]

5. Combine the results:
- The coordinates of point [tex]\( F \)[/tex] are [tex]\( (-14, 0) \)[/tex].

Thus, the coordinates of point [tex]\( F \)[/tex] are [tex]\( \boxed{(-14, 0)} \)[/tex].

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