Divide [tex]\(\frac{x^{\frac{3}{4}}}{x^{\frac{1}{6}}}\)[/tex].

A. [tex]\(x^{\frac{7}{12}}\)[/tex]
B. [tex]\(x^{\frac{11}{12}}\)[/tex]
C. [tex]\(x^{\frac{1}{6}}\)[/tex]
D. [tex]\(x\)[/tex]



Answer :

To solve the problem, we need to handle the expressions involving exponents according to the rules of exponents.

Given the expression:
[tex]\[ \frac{x^{\frac{3}{4}}}{x^{\frac{1}{6}}} \cdot x^{\frac{7}{12}} \][/tex]

First, let's address the division. According to the exponent rules, when we divide two powers with the same base, we subtract the exponents:
[tex]\[ \frac{x^{\frac{3}{4}}}{x^{\frac{1}{6}}} = x^{\frac{3}{4} - \frac{1}{6}} \][/tex]

To subtract the fractions [tex]\(\frac{3}{4}\)[/tex] and [tex]\(\frac{1}{6}\)[/tex], we need a common denominator. The common denominator for 4 and 6 is 12. Converting each fraction:

[tex]\[ \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} \][/tex]
[tex]\[ \frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12} \][/tex]

Now, subtract the exponents:

[tex]\[ \frac{9}{12} - \frac{2}{12} = \frac{9 - 2}{12} = \frac{7}{12} \][/tex]

So,
[tex]\[ \frac{x^{\frac{3}{4}}}{x^{\frac{1}{6}}} = x^{\frac{7}{12}} \][/tex]

Next, we multiply this result by [tex]\(x^{\frac{7}{12}}\)[/tex]. According to the exponent rules, when we multiply two powers with the same base, we add the exponents:

[tex]\[ x^{\frac{7}{12}} \cdot x^{\frac{7}{12}} = x^{\frac{7}{12} + \frac{7}{12}} = x^{\frac{14}{12}} = x^{\frac{7}{6}} \][/tex]

Thus, the final result is:

[tex]\[ \boxed{x^{\frac{7}{6}}} \][/tex]

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