Let's solve the system of equations step-by-step using the substitution method.
The given system of equations is:
[tex]\[
\begin{array}{l}
6x - y = 1 \quad \text{(1)} \\
4x - 3y = -11 \quad \text{(2)}
\end{array}
\][/tex]
1. Solve the first equation for [tex]\(y\)[/tex]:
[tex]\[ 6x - y = 1 \][/tex]
[tex]\[ -y = 1 - 6x \][/tex]
[tex]\[ y = 6x - 1 \][/tex]
2. Substitute [tex]\(y = 6x - 1\)[/tex] into the second equation (Equation 2):
[tex]\[ 4x - 3(6x - 1) = -11 \][/tex]
Now let's verify which of the given choices corresponds to this substitution. Simplify the above equation step by step:
[tex]\[ 4x - 3(6x - 1) = -11 \][/tex]
[tex]\[ 4x - 18x + 3 = -11 \][/tex]
Simplify further if necessary, but at this step, the new equation after substituting [tex]\(y\)[/tex] from the first equation into the second equation clearly matches:
[tex]\[ 4x - 3(6x - 1) = -11 \][/tex]
So, the correct choice is:
[tex]\[ 4x - 3(6x - 1) = -11 \][/tex]
Therefore, the answer is indeed [tex]\(\boxed{4 x-3(6 x-1)=-11}\)[/tex].
