Answer :
To find the correct internal ratio for the compound [tex]\( Al_2S_3 \)[/tex], we need to analyze its chemical formula. The formula [tex]\( Al_2S_3 \)[/tex] indicates that the compound is composed of aluminum (Al) and sulfur (S) in certain proportions. Specifically, the subscript numbers indicate the mole ratio of the elements within the compound.
1. Identify the ratio from the chemical formula:
- The subscript "2" after aluminum (Al) implies that there are 2 moles of aluminum.
- The subscript "3" after sulfur (S) implies that there are 3 moles of sulfur.
2. Write the ratio of aluminum to sulfur:
- In [tex]\( Al_2S_3 \)[/tex], the ratio of moles of aluminum to moles of sulfur is [tex]\(2 \text{ mol Al} \)[/tex] for every [tex]\(3 \text{ mol S}\)[/tex].
3. Check the given options:
- Option 1: [tex]\(\frac{2 \text{ mol Al}}{3 \text{ mol S}}\)[/tex]
- This matches the ratio determined from the chemical formula [tex]\( Al_2S_3 \)[/tex].
- Option 2: [tex]\(\frac{1 \text{ mol } S_3}{1 \text{ mol } Al_2}\)[/tex]
- This is not a standard way of expressing the internal ratio of a compound and does not simplify correctly to show the correct relationship.
- Option 3: [tex]\(\frac{2 \text{ mol S}}{3 \text{ mol Al}}\)[/tex]
- This inverts the correct ratio and is not accurate for the compound [tex]\( Al_2S_3 \)[/tex].
Thus, the correct internal ratio for the compound [tex]\( Al_2S_3 \)[/tex] is:
[tex]\[ \frac{2 \text{ mol Al}}{3 \text{ mol S}} \][/tex]
1. Identify the ratio from the chemical formula:
- The subscript "2" after aluminum (Al) implies that there are 2 moles of aluminum.
- The subscript "3" after sulfur (S) implies that there are 3 moles of sulfur.
2. Write the ratio of aluminum to sulfur:
- In [tex]\( Al_2S_3 \)[/tex], the ratio of moles of aluminum to moles of sulfur is [tex]\(2 \text{ mol Al} \)[/tex] for every [tex]\(3 \text{ mol S}\)[/tex].
3. Check the given options:
- Option 1: [tex]\(\frac{2 \text{ mol Al}}{3 \text{ mol S}}\)[/tex]
- This matches the ratio determined from the chemical formula [tex]\( Al_2S_3 \)[/tex].
- Option 2: [tex]\(\frac{1 \text{ mol } S_3}{1 \text{ mol } Al_2}\)[/tex]
- This is not a standard way of expressing the internal ratio of a compound and does not simplify correctly to show the correct relationship.
- Option 3: [tex]\(\frac{2 \text{ mol S}}{3 \text{ mol Al}}\)[/tex]
- This inverts the correct ratio and is not accurate for the compound [tex]\( Al_2S_3 \)[/tex].
Thus, the correct internal ratio for the compound [tex]\( Al_2S_3 \)[/tex] is:
[tex]\[ \frac{2 \text{ mol Al}}{3 \text{ mol S}} \][/tex]
