What is the determinant of the coefficient matrix of the system?

[tex]\[
\begin{cases}
4x - 6y + 0z = -7 \\
3x + 3y + 0z = -2 \\
2x - 12y + 0z = -1
\end{cases}
\][/tex]

A. [tex]\(-7\)[/tex]

B. [tex]\(-2\)[/tex]

C. [tex]\(-1\)[/tex]

D. [tex]\(0\)[/tex]



Answer :

To find the determinant of the coefficient matrix of the given system of equations, we follow these steps:

The system of equations is:
[tex]\[ \begin{cases} 4x - 6y + 0z = -7 \\ 3x + 3y + 0z = -2 \\ 2x - 12y + 0z = -1 \end{cases} \][/tex]

The coefficient matrix for this system is:
[tex]\[ \begin{pmatrix} 4 & -6 & 0 \\ 3 & 3 & 0 \\ 2 & -12 & 0 \end{pmatrix} \][/tex]

Next, we need to find the determinant of this 3x3 matrix. The general formula for the determinant of a 3x3 matrix [tex]\(\begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix}\)[/tex] is given by:
[tex]\[ \text{det} = a(ei - fh) - b(di - fg) + c(dh - eg) \][/tex]

For our specific matrix, the calculation would be:
[tex]\[ \text{det} = 4(3 \cdot 0 - (-12) \cdot 0) - (-6)(3 \cdot 0 - 2 \cdot 0) + 0(3 \cdot (-12) - 2 \cdot 3) \][/tex]

Simplifying each term:
- The first term is: [tex]\(4(0) = 0\)[/tex]
- The second term is: [tex]\(-6(0) = 0\)[/tex]
- The third term is: [tex]\(0\)[/tex]

Adding these up:
[tex]\[ \text{det} = 0 + 0 + 0 = 0 \][/tex]

Therefore, the determinant of the coefficient matrix is:
[tex]\[ \boxed{0} \][/tex]