Given the grades and gender summary below, find the probability that a randomly chosen student did NOT get a "B."

| Gender | A | B | C | Total |
|--------|----|----|----|-------|
| Male | 4 | 13 | 20 | 37 |
| Female | 16 | 9 | 7 | 32 |
| Total | 20 | 22 | 27 | 69 |

Probability = ______ (Please enter a reduced fraction.)



Answer :

To find the probability that a randomly chosen student did not get a "B", we need to follow these steps:

1. Determine the total number of students: According to the data, the total number of students is:
[tex]\[ 69 \][/tex]

2. Determine the total number of students who got a "B": From the given table:
[tex]\[ 22 \][/tex]

3. Calculate the number of students who did NOT get a "B":
[tex]\[ 69 - 22 = 47 \][/tex]

4. Calculate the probability that a student did NOT get a "B":
The probability is the ratio of the number of students who did NOT get a "B" to the total number of students:
[tex]\[ \frac{47}{69} \][/tex]

5. Simplify the fraction (if possible): We check if the fraction [tex]\(\frac{47}{69}\)[/tex] can be reduced. The greatest common divisor (GCD) of 47 and 69 is 1, so the fraction is already in its simplest form.

Therefore, the probability that a randomly chosen student did not get a "B" is:
[tex]\[ \boxed{\frac{47}{69}} \][/tex]