Answer :
Let's find the percent composition of hydrogen in the given sample.
The problem provides the following masses:
- Total mass of the alcohol sample: [tex]\( 43.40 \, \text{mg} \)[/tex]
- Mass of hydrogen ([tex]\( H \)[/tex]): [tex]\( 5.70 \, \text{mg} \)[/tex]
To find the percent composition of hydrogen, we follow these steps:
1. Identify the total mass of the sample: [tex]\( 43.40 \, \text{mg} \)[/tex].
2. Identify the mass of hydrogen in the sample: [tex]\( 5.70 \, \text{mg} \)[/tex].
3. Calculate the percent composition of hydrogen using the formula:
[tex]\[ \text{Percent composition of } H = \left( \frac{\text{Mass of } H}{\text{Total mass of the sample}} \right) \times 100 \][/tex]
Plugging in the given values:
[tex]\[ \text{Percent composition of } H = \left( \frac{5.70}{43.40} \right) \times 100 \][/tex]
4. Evaluate the expression:
[tex]\[ \left( \frac{5.70}{43.40} \right) \times 100 \approx 13.133640552995393 \][/tex]
Therefore, the percent composition of hydrogen in the sample is approximately [tex]\( 13.133640552995393\% \)[/tex].
The problem provides the following masses:
- Total mass of the alcohol sample: [tex]\( 43.40 \, \text{mg} \)[/tex]
- Mass of hydrogen ([tex]\( H \)[/tex]): [tex]\( 5.70 \, \text{mg} \)[/tex]
To find the percent composition of hydrogen, we follow these steps:
1. Identify the total mass of the sample: [tex]\( 43.40 \, \text{mg} \)[/tex].
2. Identify the mass of hydrogen in the sample: [tex]\( 5.70 \, \text{mg} \)[/tex].
3. Calculate the percent composition of hydrogen using the formula:
[tex]\[ \text{Percent composition of } H = \left( \frac{\text{Mass of } H}{\text{Total mass of the sample}} \right) \times 100 \][/tex]
Plugging in the given values:
[tex]\[ \text{Percent composition of } H = \left( \frac{5.70}{43.40} \right) \times 100 \][/tex]
4. Evaluate the expression:
[tex]\[ \left( \frac{5.70}{43.40} \right) \times 100 \approx 13.133640552995393 \][/tex]
Therefore, the percent composition of hydrogen in the sample is approximately [tex]\( 13.133640552995393\% \)[/tex].