To solve this problem, we need to determine the number of atoms of each element in the compound [tex]\( Na_2HPO_4 \)[/tex] and then multiply the number of each type of atom by its respective atomic number.
1. Identify the number of each type of atom in [tex]\( Na_2HPO_4 \)[/tex]:
- Sodium (Na): There are 2 sodium atoms.
- Hydrogen (H): There is 1 hydrogen atom.
- Phosphorus (P): There is 1 phosphorus atom.
- Oxygen (O): There are 4 oxygen atoms.
2. Determine the atomic numbers for each element:
- Sodium (Na) has an atomic number of 11.
- Hydrogen (H) has an atomic number of 1.
- Phosphorus (P) has an atomic number of 15.
- Oxygen (O) has an atomic number of 8.
3. Multiply the number of each type of atom by the corresponding atomic number:
- For Sodium (Na): [tex]\( 2 \times 11 = 22 \)[/tex]
- For Hydrogen (H): [tex]\( 1 \times 1 = 1 \)[/tex]
- For Phosphorus (P): [tex]\( 1 \times 15 = 15 \)[/tex]
- For Oxygen (O): [tex]\( 4 \times 8 = 32 \)[/tex]
Therefore, the final results are:
- Sodium: 22
- Hydrogen: 1
- Phosphorus: 15
- Oxygen: 32
These numerical results provide the expression of each atom in [tex]\( Na_2HPO_4 \)[/tex] as integers based on their atomic numbers.
