What is the solution of the equation [tex]\( x^2 + 4 = 0 \)[/tex]?

A. [tex]\( x = \pm \sqrt{2} \)[/tex]

B. [tex]\( x = \pm 2i \)[/tex]

C. [tex]\( x = \pm i \)[/tex]

D. [tex]\( x = \pm 2 \)[/tex]



Answer :

To solve the equation [tex]\(x^2 + 4 = 0\)[/tex], we will follow a systematic approach:

1. Rewrite the equation:
[tex]\[ x^2 + 4 = 0 \][/tex]

2. Isolate the [tex]\(x^2\)[/tex] term:
[tex]\[ x^2 = -4 \][/tex]

3. Recognize that we need to take the square root of both sides.

4. Take the square root of both sides:
[tex]\[ x = \pm \sqrt{-4} \][/tex]

5. Simplify the square root of [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{-4} = \sqrt{4 \cdot (-1)} = \sqrt{4} \cdot \sqrt{-1} \][/tex]
Knowing that [tex]\(\sqrt{4} = 2\)[/tex] and [tex]\(\sqrt{-1} = i\)[/tex]:
[tex]\[ \sqrt{-4} = 2i \][/tex]

Thus, the solutions to the equation [tex]\(x^2 + 4 = 0\)[/tex] are:
[tex]\[ x = \pm 2i \][/tex]

So, the correct answer is:
[tex]\[ x = \pm 2i \][/tex]