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6. Huey, Dewey, and Louie work at a bank. Each day, one of them is randomly selected to be a greeter for customers. Over two consecutive days, which event is least likely to occur? Show the probability as proof.

A. Dewey is not assigned at all.
B. Louie is assigned at least once.
C. Huey is assigned exactly once.
D. The same person is assigned twice.



Answer :

GinnyAnswer

Final answer:

The solution calculates the least likely event over two consecutive days at a bank based on the given probabilities.


Explanation:

To determine the least likely event over two consecutive days:

  1. Dewey not being assigned at all: Probability = (2/3) (2/3) = 4/9 = 0.444.
  2. Louie being assigned at least once: Probability = 1 - (1/3 1/3) = 8/9 = 0.888.
  3. Huey being assigned exactly once: Probability = (1/3 2/3) + (2/3 1/3) = 4/9 = 0.444.
  4. The same person being assigned twice: Probability = (1/3 1/3) + (1/3 1/3) = 2/9 = 0.222.

Therefore, the event least likely to occur over two consecutive days is Dewey not being assigned at all with a probability of 0.444.


Learn more about Probability and Events here:

https://brainly.com/question/17089724


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