Calculate the force a test charge of 0.001 coulomb would experience in the field across charged plates of 12 volts and separation of 0.4 cm.



Answer :

Answer:

force = 3 N

Explanation:

To find the force of the test charge of 0.001 C, we can use this formula:

[tex]\boxed{F=\frac{Vq}{d} }[/tex]

where:

  • F = force
  • V = voltage
  • q = charge
  • d = distance

Given:

  • V = 12 V
  • q = 0.001 C
  • d = 0.4 cm = 0.004 m

Therefore:

[tex]\displaystyle F=\frac{Vq}{d}[/tex]

[tex]\displaystyle F=\frac{12\times0.001}{0.004}[/tex]

[tex]\bf F=3\ N[/tex]