A sequence is defined recursively by [tex]\( a_n = 4 a_{n-1} \)[/tex]. The first term of the sequence is 0.5.

Which of the following is the explicit formula for the nth term of the sequence?

A. [tex]\( a_n = 4 \cdot 0.5^n \)[/tex]

B. [tex]\( a_n = 0.5 \cdot 4^n \)[/tex]

C. [tex]\( a_n = 4 \cdot 0.5^{(n-1)} \)[/tex]

D. [tex]\( a_n = 0.5 \cdot 4^{(n+1)} \)[/tex]

E. [tex]\( a_n = 0.5 \cdot 4^{(n-1)} \)[/tex]



Answer :

To find the explicit formula for the nth term of the sequence defined recursively by [tex]\( a_n = 4a_{n-1} \)[/tex] with the first term given as [tex]\( a_1 = 0.5 \)[/tex], let’s proceed step by step:

1. Understand the Recursive Definition:
The sequence is defined such that each term is 4 times the previous term:
[tex]\[ a_n = 4a_{n-1} \][/tex]

2. Determine the Pattern:
Let's calculate the first few terms to observe a pattern:
- The first term is [tex]\( a_1 = 0.5 \)[/tex]
- The second term is [tex]\( a_2 = 4a_1 = 4 \cdot 0.5 = 2 \)[/tex]
- The third term is [tex]\( a_3 = 4a_2 = 4 \cdot 2 = 8 \)[/tex]
- The fourth term is [tex]\( a_4 = 4a_3 = 4 \cdot 8 = 32 \)[/tex]

3. Identify the General Form:
We see that the terms of the sequence are increasing by a factor of 4 each time. To express this relationship generally, we can write:
[tex]\[ a_2 = 4 \cdot 0.5 = 0.5 \cdot 4^1 \][/tex]
[tex]\[ a_3 = 4 \cdot a_2 = 4 \cdot (0.5 \cdot 4^1) = 0.5 \cdot 4^2 \][/tex]
[tex]\[ a_4 = 4 \cdot a_3 = 4 \cdot (0.5 \cdot 4^2) = 0.5 \cdot 4^3 \][/tex]
From this pattern, we can infer that:
[tex]\[ a_n = 0.5 \cdot 4^{n-1} \][/tex]

4. Confirm the Explicit Formula:
The general formula for the nth term of the sequence is:
[tex]\[ a_n = 0.5 \cdot 4^{n-1} \][/tex]
This matches the option E which is [tex]\( a_n = 0.5 \cdot 4^{n-1} \)[/tex].

Therefore, the correct explicit formula for the nth term of the sequence is given by option E:
[tex]\[ a_n = 0.5 \cdot 4^{(n-1)} \][/tex]

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