At a phone store, the purchases for one month are recorded in the table below:

[tex]\[
\begin{array}{|l|c|c|c|}
\hline
& \text{Phone I} & \text{Phone II} & \text{Phone III} \\
\hline
\text{Mini} & 7 & 23 & 31 \\
\hline
\text{Standard} & 43 & 41 & 29 \\
\hline
\text{Maximum} & 2 & 17 & 13 \\
\hline
\end{array}
\][/tex]

If we choose a customer at random, what is the probability that they have purchased a mini sized Phone II?

[tex]\( P(\text{Mini and Phone II}) = \square \)[/tex]

Give your answer in simplest form.



Answer :

To determine the probability that a randomly chosen customer has purchased a mini sized Phone II, follow these steps:

1. Determine the total number of customers:
Sum up all the customers who have made a purchase, as provided in the table:

[tex]\[ \begin{aligned} &\text{Mini (Phone I, Phone II, Phone III)}: &7 + 23 + 31 = 61 \\ &\text{Standard (Phone I, Phone II, Phone III)}: &43 + 41 + 29 = 113 \\ &\text{Maximum (Phone I, Phone II, Phone III)}: &2 + 17 + 13 = 32 \\ \end{aligned} \][/tex]

Adding these totals together gives the overall number of customers:

[tex]\[ 61 + 113 + 32 = 206 \][/tex]

So, the total number of customers is 206.

2. Identify the number of customers who purchased a mini sized Phone II:
From the table, the number of customers who purchased a mini sized Phone II is given as:

[tex]\[ 23 \][/tex]

3. Calculate the probability:
The probability that a randomly selected customer purchased a mini sized Phone II is the ratio of the number of mini sized Phone II customers to the total number of customers. Hence,

[tex]\[ P(\text{Mini and Phone II}) = \frac{\text{Number of mini sized Phone II customers}}{\text{Total number of customers}} = \frac{23}{206} \][/tex]

4. Simplified form:
Simplify the fraction [tex]\(\frac{23}{206}\)[/tex]. Note that 23 is a prime number and does not divide evenly into 206, so the fraction is already in its simplest form.

Therefore, the probability that a randomly chosen customer purchased a mini sized Phone II is:
[tex]\[ P(\text{Mini and Phone II}) = \frac{23}{206} \][/tex]