What is the true solution to [tex]\( \ln 20 + \ln 5 = 2 \ln x \)[/tex]?

A. [tex]\( x = 5 \)[/tex]
B. [tex]\( x = 10 \)[/tex]
C. [tex]\( x = 50 \)[/tex]
D. [tex]\( x = 100 \)[/tex]



Answer :

Let's solve the equation step-by-step.

The given equation is:

[tex]\[ \ln 20 + \ln 5 = 2 \ln x \][/tex]

### Step 1: Combine the logarithmic terms on the left-hand side
We can use the property of logarithms that [tex]\(\ln a + \ln b = \ln(ab)\)[/tex] to combine the logarithms on the left side:

[tex]\[ \ln(20 \cdot 5) = 2 \ln x \][/tex]

### Step 2: Simplify the combined logarithmic term
Next, multiply the numbers inside the logarithm:

[tex]\[ \ln(100) = 2 \ln x \][/tex]

### Step 3: Use the property of logarithms to simplify further
We can use the property that [tex]\(k \ln a = \ln(a^k)\)[/tex]. Here, [tex]\(k = 2\)[/tex]:

[tex]\[ \ln(100) = \ln(x^2) \][/tex]

### Step 4: Equate the arguments of the logarithms
If [tex]\(\ln(a) = \ln(b)\)[/tex], then [tex]\(a = b\)[/tex]. Therefore, we equate the arguments of the logarithms:

[tex]\[ 100 = x^2 \][/tex]

### Step 5: Solve for [tex]\(x\)[/tex]
To find [tex]\(x\)[/tex], we take the square root of both sides:

[tex]\[ x = \sqrt{100} \][/tex]

[tex]\[ x = 10 \][/tex]

So, the solution to the equation [tex]\(\ln 20 + \ln 5 = 2 \ln x\)[/tex] is:

[tex]\[ x = 10 \][/tex]

Therefore, the correct answer is:

[tex]\[ \boxed{x = 10} \][/tex]