The table lists the number of protons, electrons, and neutrons in a certain radioactive nuclide.

[tex]\[
\begin{array}{|c|c|c|}
\hline
\text{Electrons} & \text{Protons} & \text{Neutrons} \\
\hline
11 & 11 & 13 \\
\hline
\end{array}
\][/tex]

Which is the symbol of this radioactive nuclide?

A. [tex]\(\prescript{24}{}{\text{Na}}_{11}\)[/tex]
B. [tex]\(\prescript{22}{}{\text{Na}}_{11}\)[/tex]
C. [tex]\(\prescript{13}{}{\text{Al}}_{11}\)[/tex]
D. [tex]\(\prescript{24}{}{\text{Al}}_{13}\)[/tex]



Answer :

To determine the symbol of the given radioactive nuclide, we need to follow a series of steps based on the provided information.

### Step 1: Identify the Atomic Number
- The atomic number is equal to the number of protons in the nucleus.
- From the table, we see that the number of protons is 11.

The atomic number 11 corresponds to the element Sodium (Na) on the periodic table.

### Step 2: Calculate the Mass Number
- The mass number is the sum of the number of protons and neutrons in the nucleus.
- From the table, the number of neutrons is given as 13.

Thus, the mass number [tex]\( A \)[/tex] is calculated as:
[tex]\[ A = \text{Number of Protons} + \text{Number of Neutrons} \][/tex]
[tex]\[ A = 11 + 13 \][/tex]
[tex]\[ A = 24 \][/tex]

### Step 3: Write the Isotope Notation
The isotope notation includes the element symbol (which we determined to be Na), the atomic number (11) as a subscript, and the mass number (24) as a superscript.

So, the isotope notation is:
[tex]\[ \mathbf{{}_{11}^{24} \text{Na}} \][/tex]

### Step 4: Match with the Given Choices
We now match our isotope notation with the given choices:

1. [tex]\({}_{11}^{24} \text{Na} \)[/tex]
2. [tex]\({}_{11}^{22} \text{Na} \)[/tex]
3. [tex]\({}_{11}^{13} \text{Al} \)[/tex]
4. [tex]\({}_{13}^{24} \text{Al} \)[/tex]

The correct symbol of the radioactive nuclide, based on our calculation, is:
[tex]\[ \mathbf{{}_{11}^{24} \text{Na}} \][/tex]

### Conclusion
Thus, among the given options, the correct symbol of the radioactive nuclide is:
[tex]\[ \boxed{ {}_{11}^{24} \text{Na} } \][/tex]