Answer :

To determine the number of oxygen (O) atoms in the compound [tex]\(Zn(ClO_3)_2\)[/tex], follow these steps:

1. Analyze the Composition:
- The compound [tex]\(Zn(ClO_3)_2\)[/tex] consists of one zinc (Zn) atom and two chlorate ([tex]\(ClO_3\)[/tex]) groups.

2. Inspect the Chlorate Group:
- Each chlorate group ([tex]\(ClO_3\)[/tex]) contains:
- 1 chlorine (Cl) atom
- 3 oxygen (O) atoms

3. Calculate the Total Oxygen Atoms:
- Since there are 2 chlorate ([tex]\(ClO_3\)[/tex]) groups in [tex]\(Zn(ClO_3)_2\)[/tex], we calculate the total number of oxygen atoms by multiplying the number of oxygen atoms in one chlorate group by the number of chlorate groups.

[tex]\[ \text{Total oxygen atoms} = 3 \text{ (oxygen atoms per \(ClO_3\))} \times 2 \text{ (chlorate groups)} \][/tex]

[tex]\[ \text{Total oxygen atoms} = 6 \][/tex]

Therefore, the number of oxygen atoms in [tex]\(Zn(ClO_3)_2\)[/tex] is [tex]\( \boxed{6} \)[/tex].