To determine the boiling point of R-134a at atmospheric pressure, we need to identify the temperature at which it transitions from a liquid to a gas under standard conditions.
Given the various options:
- Option (a): [tex]\(-15^{\circ} F \left(-26.1^{\circ} C\right)\)[/tex]
- Option (b): [tex]\(32^{\circ} F \left(0^{\circ} C\right)\)[/tex]
- Option (c): [tex]\(100^{\circ} F \left(37.8^{\circ} C\right)\)[/tex]
- Option (d): [tex]\(212^{\circ} F \left(100.0^{\circ} C\right)\)[/tex]
We know that:
1. Water boils at [tex]\(212^{\circ} F\)[/tex] ([tex]\(100^{\circ} C\)[/tex]) at atmospheric pressure, which means option (d) refers to water's boiling point, not R-134a.
2. [tex]\(32^{\circ} F\)[/tex] ([tex]\(0^{\circ} C\)[/tex]) is the melting/freezing point of water. This cannot be the boiling point of R-134a, eliminating option (b).
3. [tex]\(100^{\circ} F\)[/tex] ([tex]\(37.8^{\circ} C\)[/tex]) might represent a warm day, not a boiling point of a refrigerant, eliminating option (c).
Given the specifics and what we understand about refrigerants, the boiling point of R-134a at atmospheric pressure aligns with option (a): [tex]\(-15^{\circ} F\)[/tex] ([tex]\(-26.1^{\circ} C\)[/tex]).
Thus, the correct answer is:
(a) [tex]\(-15^{\circ} F \left(-26.1^{\circ} C\right)\)[/tex]
