What is the equation of the line graphed below?
A. y=-1x
B. y = 5x
OC. y=x
D. v=-5x
(1,5)
5
![What is the equation of the line graphed belowA y1xB y 5xOC yxD v5x155 class=](https://us-static.z-dn.net/files/d8a/4c685b27bba4aa82ea386e74af33db44.png)
Answer:
B
Step-by-step explanation:
The equation of a line passing through the origin is
• y = mx ( m is the slope )
calculate the slope m, using the slope formula
• m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
let (x₁, y₁ ) = (0, 0 ) and (x₂, y₂ ) = (1, 5) ← 2 points on the line
substitute these values into the formula for m
m = [tex]\frac{5-0}{1-0}[/tex] = [tex]\frac{5}{1}[/tex] = 5
y = 5x ← equation of line