A [tex][tex]$7.00 \, \text{kg}$[/tex][/tex] bowling ball is held [tex][tex]$2.00 \, \text{m}$[/tex][/tex] above the ground. Using [tex][tex]$g=9.80 \, \text{m/s}^2$[/tex][/tex], how much energy does the bowling ball have due to its position?

A. [tex][tex]$68.6 \, \text{J}$[/tex][/tex]
B. [tex][tex]$137 \, \text{J}$[/tex][/tex]
C. [tex][tex]$274 \, \text{J}$[/tex][/tex]
D. [tex][tex]$960 \, \text{J}$[/tex][/tex]



Answer :

To determine the amount of energy a bowling ball has due to its position above the ground, we need to calculate its gravitational potential energy (GPE). Gravitational potential energy can be calculated using the formula:

[tex]\[ \text{GPE} = m \times g \times h \][/tex]

where
- [tex]\( m \)[/tex] is the mass of the object,
- [tex]\( g \)[/tex] is the acceleration due to gravity, and
- [tex]\( h \)[/tex] is the height above the ground.

Given:
- [tex]\( m = 7.00 \, \text{kg} \)[/tex]
- [tex]\( g = 9.80 \, \text{m/s}^2 \)[/tex]
- [tex]\( h = 2.00 \, \text{m} \)[/tex]

Now, substitute these values into the formula:

[tex]\[ \text{GPE} = 7.00 \, \text{kg} \times 9.80 \, \text{m/s}^2 \times 2.00 \, \text{m} \][/tex]

First, do the multiplication for mass and gravity:
[tex]\[ 7.00 \times 9.80 = 68.6 \][/tex]

Then multiply this result by the height:
[tex]\[ 68.6 \times 2.00 = 137.2 \, \text{J} \][/tex]

So, the gravitational potential energy of the bowling ball is approximately [tex]\( 137.2 \, \text{J} \)[/tex].

Therefore, the closest answer choice is:
[tex]\[ \boxed{137 \, \text{J}} \][/tex]