9. Round off each of the following numbers to the indicated number of significant figures:

a. 0.45555 (4 sig figs)
b. 292.49 (3 sig figs)
c. 17.0051 (4 sig figs)
d. 432.969 (5 sig figs)

10. Evaluate each of the following, and write the answer to the appropriate number of significant figures:

a. [tex][tex]$1.094 \times 10^5 - 1.073 \times 10^4$[/tex][/tex]
b. [tex][tex]$\left(3.923 \times 10^2 \, \text{cm}\right) \left(2.94 \, \text{cm}\right) \left(4.093 \times 10^{-3} \, \text{cm}\right)$[/tex][/tex]
c. [tex][tex]$\left(2.932 \times 10^4 \, \text{m}\right) \left[2.404 \times 10^2 \, \text{m} + 1.32 \times 10^1 \, \text{m}\right]$[/tex][/tex]
d. [tex][tex]$\left[2.34 \times 10^2 \, \text{g} + 4.443 \times 10^{-1} \, \text{g}\right] \div (0.0323 \, \text{mL})$[/tex][/tex]

1. How many dozen eggs are there in 48 eggs?



Answer :

Let's solve each of the questions step-by-step:

### 9. Round off each of the following numbers to the indicated number of significant figures:
a. 0.45555 (4 sig figs):
- Original number: 0.45555
- Considering the first 4 significant figures: 0.4555
- Rounding off the 5th figure (which is 5), we round up the fourth figure.

Result: 0.4556

b. 292.49 (3 sig figs):
- Original number: 292.49
- Considering the first 3 significant figures: 292
- The number after the third figure is 0.49; since the first figure after the cutoff is '4', we round down.

Result: 292

c. 17.0051 (4 sig figs):
- Original number: 17.0051
- Considering the first 4 significant figures: 17.00
- The number after the fourth figure is 51; since the first figure after the cutoff is '5', we round up.

Result: 17.01

d. 432.969 (5 sig figs):
- Original number: 432.969
- Considering the first 5 significant figures: 432.96
- The number after the fifth figure is 9; since the first figure after the cutoff is '9', we round up.

Result: 432.97


### 10. Evaluate each of the following, and write the answer to the appropriate number of significant figures:
a. [tex]\(1.094 \times 10^5 - 1.073 \times 10^4\)[/tex]:
- Convert both numbers to the same exponent: [tex]\(1.073 \times 10^4\)[/tex] becomes [tex]\(0.1073 \times 10^5\)[/tex]
- Subtract: [tex]\(1.094 \times 10^5 - 0.1073 \times 10^5 = 0.9867 \times 10^5\)[/tex].
- The initial precision is 4 significant figures.

Result: [tex]\(0.9867 \times 10^5\)[/tex] or [tex]\(98,670\)[/tex]

b. [tex]\(\left(3.923 \times 10^2 \text{ cm}\right)\left(2.94 \text{ cm}\right)\left(4.093 \times 10^{-3} \text{ cm}\right)\)[/tex]:
- Multiply the constants: [tex]\(3.923 \times 2.94 \times 4.093 = 47.20855\)[/tex].
- Combine exponents: [tex]\(10^2 \times 10^{-3} = 10^{-1}\)[/tex].
- Total multiplication: [tex]\(47.20855 \times 10^{-1} = 4.720855 \text{ cm}^3\)[/tex] (Rounded to 3 significant figures as per the lease precise figure [tex]\(2.94\)[/tex]).

Result: [tex]\(4.72 \text{ cm}^3\)[/tex]

c. [tex]\(\left(2.932 \times 10^4 \text{ m}\right)[2.404 \times 10^2 \text{ m} + 1.32 \times 10^1 \text{ m}]\)[/tex]:
- Perform addition inside brackets: [tex]\(2.404 \times 10^2 + 1.32 \times 10^1 = 2.536 \times 10^2 \text{ m}\)[/tex].
- Multiply: [tex]\(2.932 \times 10^4 \times 2.536 \times 10^2 = 7.433952 \times 10^6 \text{ m}^2\)[/tex].
- Round to the appropriate precision based on the least precise figure (3 sig figs from [tex]\(1.32 \times 10^1\)[/tex]).

Result: [tex]\(7.43 \times 10^6 \text{ m}^2\)[/tex]

d. [tex]\(\left[2.34 \times 10^2 \text{ g} + 4.443 \times 10^{-1} \text{ g}\right] / (0.0323 \text{ mL})\)[/tex]:
- Perform addition inside brackets: [tex]\(2.34 \times 10^2 + 0.4443 = 234.4443 \text{ g}\)[/tex].
- Divide: [tex]\(234.4443 / 0.0323 = 7250.45944\)[/tex].
- Round to the appropriate precision based on the least precise figure (3 sig figs from [tex]\(0.0323\)[/tex]).

Result: [tex]\(7.25 \times 10^3 \text{ g/mL}\)[/tex]

### 1. How many dozen eggs are there in 48 eggs?

To find out how many dozen (sets of 12) eggs are in 48 eggs:
- Divide the total number of eggs by the number of eggs in one dozen:
[tex]\[ \text{Number of dozens} = \frac{48 \text{ eggs}}{12 \text{ eggs/dozen}} = 4 \text{ dozens} \][/tex]

Result: 4 dozens