Sure! Let's examine the expression [tex]\(32 \cdot y\)[/tex]. We'll use the commutative property of multiplication, which states that the order of factors in a multiplication operation does not change the product. Therefore, [tex]\(a \cdot b\)[/tex] is the same as [tex]\(b \cdot a\)[/tex].
Given the expression [tex]\(32 \cdot y\)[/tex]:
1. We can rewrite it by switching the order of the factors, so it becomes:
[tex]\[
y \cdot 32
\][/tex]
Therefore, the expression [tex]\(32 \cdot y\)[/tex], when rewritten using the commutative property of multiplication, is [tex]\(y \cdot 32\)[/tex].
So both expressions [tex]\(32 \cdot y\)[/tex] and [tex]\(y \cdot 32\)[/tex] are equivalent, meaning:
[tex]\[
32 \cdot y = y \cdot 32
\][/tex]
This is the detailed step-by-step solution to the given problem.
